Principle

When very high current strengths are required on a technical scale, e.g. for welding equipment or electric smelting furnaces, then so-called heavy current transformers are used. Their secondary coils have only a few turns of large diameter wire.
In the case of an ideal transformer under load, the primary and secondary performances are equal, so that I_s  ∕ I_p  = N_p  ∕ N_s is valid. The students should recognise from this experiment that the ratio I_s  ∕ I_p increases with increasing load, so that I_s  ∕ I_p  ≈ N_p  ∕ N_s is true for the transformer under load.

Benefits

• No additional cable connections between the building blocks needed - clear arragned and quick setup
• Contact saftey due to puzzle blocks system
• Corrosion-free gold plated contacts
• Doubled earning sucess: Electric circuit diagram on top, real components can be seen unterside

Tasks

How does a transformer perform under load?

Set up a model of a transformer and use it to examine which conformity to law is given when the transformer is under load.